To evaluate (1+x)^m series by counting upto n terms

/*To expand (1+x)^m series*/
#include<stdio.h>
#include<math.h>
int main()
{
    float sum, term, x;
    int n, i, m;
    printf("Enter the values of x & No. of countable terms(n):\n");
    scanf("%f %d", &x, &n);
    printf("Enter the power(m):");
    scanf("%d", &m);
    sum=1+m*x;
        term=m*x;       
    for(i=1;i<=(n-1);i++)
    {
        term =term*x*(m-i)/(i+1);
        sum=sum+term;
    }
    printf("\n(1+(%f))^%d=%f \n", x, m, sum);
    return(0);
}